Chiron
forum member
I'm thinking out loud here, so bear with me. If you have a pre-pump flow of some number Q, the flow coming out of the first pump would be Q plus a constant (dependent on pump selection, speed, etc - let's say the pump can double the flow Q). For the sake of simplicity, call it 2Q. Now, if you run it directly into another identical pump, you'd increase the flow linearly by the same amount as the first pump (3Q in this case). If you ran it from the first pump through an intercooler, the flow entering the second pump would be 2Q-L (L=losses in the intercooler). Thus, flow out of the second pump would be 3Q-L.The reason I stated across the greatest restriction is the fact that that will be the largest pressure differential.
To get the most flow through that restriction you create the greatest pressure differential across it.
Outlet of one pump producing the maximum positive pressure and the inlet of the other creating the maximum negative pressure.
Any input from the rest of the class?